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昨天写的程序的那个延迟算法实在是太龌龊了，自己都看不下去了··

今天补上用定时器中断和查询的延迟方法。

 这个是中断法

#include <AT89X51.H>

unsigned char code dispcode[]={0x3f,0x06,0x5b,0x4f,
0x66,0x6d,0x7d,0x07,
0x7f,0x6f,0x77,0x7c,
0x39,0x5e,0x79,0x71,0x00};  //这个码字貌似有点问题，不过先不管这些细节了····
unsigned char second;
unsigned char tcount;    TMOD=0x01;
   TH0=(65536-50000)/256;
   TL0=(65536-50000)%256;    //分别对高位和地位赋初值 
   TR0=1;
   ET0=1;
   EA=1;
   tcount=0;
   second=0;
   P0=dispcode[second/10];
   P2=dispcode[second%10];
   while(1);
      }

    void t0(void) interrupt 1 using 0           //使用中断向量1，如果是用的计数器1就要用中断向量4
     {
       tcount++;
       if(tcount==20)
           {
              tcount=0;
              second++;
              if(second==60)
                {
                  second=0;
                 }
              P0=dispcode[second/10];
              P2=dispcode[second%10];
           }
      TH0=(65536-50000)/256;
      TL0=(65536-50000)%256;
    }

下面是用的查询的方法，个人感觉比中断的方法简单。

#include <AT89X51.H>

unsigned char code dispcode[]={0x3f,0x06,0x5b,0x4f,
0x66,0x6d,0x7d,0x07,
0x7f,0x6f,0x77,0x7c,
0x39,0x5e,0x79,0x71,0x00};
unsigned char second;
unsigned char tcount;

void main(void)
{
TMOD=0x01;
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
TR0=1;
tcount=0;
second=0;
P0=dispcode[second/10];
P2=dispcode[second%10];
while(1)
{
  if(TF0==1)
  {
    tcount++;
    if(tcount==20)
      {
         tcount=0;
         second++;
         if(second==60)
          {
              second=0;
          }
         P0=dispcode[second/10];
         P2=dispcode[second%10];
      }
     TF0=0;
     TH0=(65536-50000)/256;
     TL0=(65536-50000)%256;
}
}
}